hdu 5585 Numbers-白红宇

hdu 5585 Numbers

阅读量：6186 次

发布时间：2019-06-21

本文共 1152 字，大约阅读时间需要 3 分钟。

Problem Description

There is a number N.You should output "YES" if N is a multiple of 2, 3 or 5,otherwise output "NO".

Input

There are multiple test cases, no more than 1000 cases.For each case,the line contains a integer N.(0
      
       <1030)

Output

For each test case,output the answer in a line.

Sample Input

Sample Output

YESYESYESNO

Source

读入%s字符串

2和5看大数的最后一位，3就把所有的位加起来看看是不是3的倍数

1 #pragma comment(linker, "/STACK:1024000000,1024000000") 2 #include
       
         3 #include
        
          4 #include
         
           5 #include
          
            6 #include
           
             7 #include
            
              8 #include
             
               9 #include
              
               10 #include
               
                11 #include
                12 #include
                 
                  13 #include
                  
                   14 #include 
                   
                    15 using namespace std;16 #define PI acos(-1.0)17 #define max(a,b) (a) > (b) ? (a) : (b)18 #define min(a,b) (a) < (b) ? (a) : (b)19 #define ll long long20 #define eps 1e-1021 #define MOD 100000000722 #define N 100000023 #define inf 1e1224 char s[36];25 int main()26 {27 28 29 while(scanf("%s",s)!=EOF){30 int len=strlen(s);31 //printf("len=%d\n",len);32 int sum=0;33 for(int i=0;i